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X^2-34X=289
We move all terms to the left:
X^2-34X-(289)=0
a = 1; b = -34; c = -289;
Δ = b2-4ac
Δ = -342-4·1·(-289)
Δ = 2312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2312}=\sqrt{1156*2}=\sqrt{1156}*\sqrt{2}=34\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34\sqrt{2}}{2*1}=\frac{34-34\sqrt{2}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34\sqrt{2}}{2*1}=\frac{34+34\sqrt{2}}{2} $
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